Intuitively, I don't think this will work. PVC is just too flexible.
/dredges up knowledge from college engineering courses . .
Here are the physical properties of rigid grade PVC:
Tensile Strength, Ultimate 29.0 - 48.3 MPa
4210 - 7000 psi Average value: 41.6 MPa
Tensile Strength, Yield 31.0 - 55.0 MPa
4500 - 7980 psi Average value: 43.3 MPa
Elongation at Break 20.0 - 230 % 20.0 - 230 % Average value: 119 %
Elongation at Yield 5.00 - 6.00 % 5.00 - 6.00 % Average value: 5.46 %
Modulus of Elasticity 2.34 - 3.10 GPa 340 - 450 ksi Average value: 2.67 GPa
Flexural Modulus 2.28 - 2.96 GPa 331 - 429 ksi Average value: 2.52 GPa
Here are the physical properties of 6061T6 Aluminum:
Ultimate Tensile Strength 310 MPa 45,000 psi AA; Typical
Tensile Yield Strength 276 MPa 40,000 psi AA; Typical
Elongation at Break 12.0 % @Thickness 1.59 mm 12.0 % @Thickness 0.0625 in AA; Typical
17.0 % @Diameter 12.7 mm 17.0 % @Diameter 0.500 in AA; Typical
Modulus of Elasticity 68.9 GPa 10000 ksi AA; Typical; Average of tension and compression. Compression modulus is about 2% greater than tensile modulus.
Notched Tensile Strength 324 MPa 47000 psi 2.5 cm width x 0.16 cm thick side-notched specimen, Kt = 17.
Ultimate Bearing Strength 607 MPa 88000 psi Edge distance/pin diameter = 2.0
Bearing Yield Strength 386 MPa 56000 psi Edge distance/pin diameter = 2.0
Poissons Ratio 0.330 0.330 Estimated from trends in similar Al alloys.
Fatigue Strength 96.5 MPa
@# of Cycles 5.00e+8 14000 psi
@# of Cycles 5.00e+8 completely reversed stress; RR Moore machine/specimen
Fracture Toughness 29.0 MPa-m½ 26.4 ksi-in½ KIC; TL orientation.
Machinability 50 % 50 % 0-100 Scale of Aluminum Alloys
Shear Modulus 26.0 GPa 3770 ksi Estimated from similar Al alloys.
Shear Strength 207 MPa 30000 psi
Aluminum is roughly ten times stronger than PVC, although PVC is considerably more flexible and will bend much further before it breaks.
You could design a PVC pipe that has the same bending properties of an aluminum tube. But it would have to have a much higher second moment of area to compensate for the difference in tensile strength. You can calculate that for a tube with the following formula:

Where Do is the outside diameter, Di is the inside diameter; ro is the outside radius, ri is the inside radius.
Then calculate the stress:

Where y = the perpendicular distance to the centroid of the cross-sectional area - roughly ri+(ro-ri)
M = the bending moment
Ix = the second moment of area about x-axis
Translation - bigger diameter, thicker walls.
OK, I'll go away now.